bobc1 Senior Heliman Location: Southern California
| The force/thrust created by a threaded bolt/screw (essentially an inclined plane) is determined by the thread pitch & torque. F = 2T(3.1416 Pi)/P where F = force, T = torque, P = thread pitch.
The above numbers would represent a perfect scenario without taking into account thread friction that can account for a very high percentage of the torque & the fact that a 4mm diameter bolt should break before exerting the above forces.
I believe that the most force that a high quality 4MM (.1575" diameter bolt with 150,000 PSI tensile strength should be able to create without damage is approximately 3,000 lbs
Cross section (not counting threads) is (3.1416 Pi)R squared. R = D/2. (3.1416 Pi)(.0787)(.0787) = .0195 X 150,000 PSI = 2,921 lbs.
EDIT: I don't know why the smiley icon shows up after the .1575" several lines above. It should be a ) but I don't seem to be able to change it. |